10=(3)(0.5)/x^2

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Solution for 10=(3)(0.5)/x^2 equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

10 = (0.5*3)/(x^2) // - (0.5*3)/(x^2)

10-((0.5*3)/(x^2)) = 0

10-1.5*x^-2 = 0

-1.5*x^-2 = -10 // : -1.5

x^-2 = 6.66666667

-2 < 0

1/(x^2) = 6.66666667 // * x^2

1 = 6.66666667*x^2 // : 6.66666667

0.15 = x^2

x^2 = 0.15 // ^ 1/2

abs(x) = 0.15^(1/2)

x = 0.15^(1/2) or x = -0.15^(1/2)

x in { 0.15^(1/2), -0.15^(1/2) }

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